IPv6 addresses are 128-bit... so does this mean we can get a subnet of 2^64 or 2^72 IPv6 addresses?! Is there any charge for these subnets or are they free too?

I'm only asking since it sounds like a really big range, so I'm surprised you can offer them

Hello,

http://www.linode.com/IPv6/#can-i-get-m ... v6-address

-Chris

Yes, those figures are correct. AFAIK there is no charge, you just need to open a support ticket to request them.

Yes, if you read the page you'd just linked to, you'd notice I actually quoted it

I was only asking for some confirmation, but GLaDOSDan has done so, so this question is answered now. Thank you!

This just in, Junior members know more about Linode than Linode staff!

Please don't say things like that, I know you are joking but I didn't mean to embarrass the staff...

/64 is the minimum subnet size typically used; giving end users a /56 or even a /48 is common and recommended practice*. Yes, the IPv6 designers were a bit nuts, but when ISPs typically have a /32 at minimum -- Linode has several -- there's a lot of room to go nuts in.

* That's more aimed at normal end user ISPs -- i.e. cable, DSL, etc. -- whose users probably have a $50 router or two, than a VPS provider, though.

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Matt Nordhoff (aka Peng on IRC)

It's recommended practice to be wasteful?

A /64 block is certainly useful because it allows stateless autoconfiguration within a network you control. A /56 block can be useful because it allows you to hand out /64 blocks if you need to for some reason. If you're not an ISP, you don't really need a /48 block or anything larger. If you run out of /64 blocks in your /56 block, you can just get another /56 block instead.

See RFC 6177 for the current recommendations.

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